for which rational expression is -5 an excluded value of x?\n$\frac{x - 5}{6}$\n$\frac{x +…

Explanation:

Step1: Recall excluded - value rule

Excluded values of a rational expression $\frac{a}{b}$ are values of the variable that make the denominator $b = 0$.

Step2: Check each option

For $\frac{x - 5}{6}$, the denominator is 6. Since $6\neq0$ for all real - values of $x$, there are no excluded values. For $\frac{x + 5}{6}$, the denominator is 6. Since $6\neq0$ for all real - values of $x$, there are no excluded values. For $\frac{6}{x - 5}$, set the denominator $x−5 = 0$. Solving for $x$ gives $x = 5$. For $\frac{6}{x + 5}$, set the denominator $x + 5=0$. Solving for $x$ gives $x=-5$.

Answer:

$\frac{6}{x + 5}$