read the problem. jordan and roman travel the same route to work. jordan leaves for work one morning and…

read the problem. jordan and roman travel the same route to work. jordan leaves for work one morning and drives at a rate, r, of 56 mph. roman leaves the house soon after, when jordan has already traveled 2 mi. roman drives at a rate of 60 mph. how long after jordan leaves home will roman catch up to her? how many miles into their commute will this occur? which system of equations models this problem? d = 56t d = 58t d = 56t d = 62t d = 56t d = 60t - 2 d = 56t d = 60t + 2 done
Answer
Explanation:
Step1: Recall the distance - rate - time formula
The formula for distance $d$ is $d = rt$, where $r$ is the rate and $t$ is the time. For Jordan, his rate $r_J=56$ mph, so the distance he travels $d$ as a function of time $t$ (in hours) is $d = 56t$.
Step2: Analyze Roman's distance
Roman starts when Jordan has already traveled 2 miles. Roman's rate $r_R = 60$ mph. The distance Roman travels $d$ as a function of time $t$ (the time since Jordan left) is $d=60t - 2$ (we subtract 2 because Jordan had a 2 - mile head - start).
Answer:
$d = 56t$ $d = 60t - 2$