a rectangles length is 5 inches more than twice its width. its area is 50 square inches. which equation can…

a rectangles length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w?\n2w(2w + 5) = 50\n2w(w + 5) = 50\nw(2w + 5) = 50\nw(w + 5) = 50

a rectangles length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w?\n2w(2w + 5) = 50\n2w(w + 5) = 50\nw(2w + 5) = 50\nw(w + 5) = 50

Answer

Explanation:

Step1: Express the length in terms of width

Let the width of the rectangle be ( w ). The length is 5 inches more than twice its width, so the length ( l = 2w + 5 ).

Step2: Use the area formula for a rectangle

The area formula for a rectangle is ( A=l\times w ). Given that ( A = 50 ) square inches. Substitute ( l=2w + 5 ) into the area formula: ( w(2w + 5)=50 ).

Answer:

C. ( w(2w + 5)=50 )