a rectangular pyramid is shown below. which diagram is a net for this pyramid? what is the surface area of…

Explanation:

Step1: Identify base and lateral - face dimensions

The base of the rectangular pyramid has length $l = 32$ in and width $w=10$ in. The two pairs of triangular faces have dimensions: One pair has base $b_1 = 32$ in and height $h_1 = 13$ in, and the other pair has base $b_2 = 10$ in and height $h_2 = 20$ in.

Step2: Calculate base - area

The area of the rectangular base $A_{base}=l\times w$. So, $A_{base}=32\times10 = 320$ square inches.

Step3: Calculate area of first - pair of triangular faces

The area of a triangle is $A=\frac{1}{2}bh$. For the pair of triangles with $b = 32$ in and $h = 13$ in, the combined area $A_1=2\times\frac{1}{2}\times32\times13=32\times13 = 416$ square inches.

Step4: Calculate area of second - pair of triangular faces

For the pair of triangles with $b = 10$ in and $h = 20$ in, the combined area $A_2=2\times\frac{1}{2}\times10\times20= 200$ square inches.

Step5: Calculate total surface area

The total surface area $A = A_{base}+A_1+A_2$. So, $A=320 + 416+200=936$ square inches.

Answer:

936