a rectangular pyramid is shown below. which diagram is a net for this pyramid? what is the surface area of…

Explanation:

Step1: Analyze base area

The base is a rectangle with length $l = 17$ cm and width $w=17$ cm. The area of the base $A_{base}=l\times w = 17\times17=289$ square - cm.

Step2: Analyze area of two pairs of triangular faces

For the pair of triangular faces with base $b = 17$ cm and height $h = 10$ cm, the area of one such triangle is $A_{1}=\frac{1}{2}\times b\times h=\frac{1}{2}\times17\times10 = 85$ square - cm. The area of the two such triangles is $2A_{1}=2\times85 = 170$ square - cm. For the other pair of triangular faces with base $b = 17$ cm and height $h = 10$ cm, the area of one such triangle is also $A_{2}=\frac{1}{2}\times b\times h=\frac{1}{2}\times17\times10 = 85$ square - cm. The area of the two such triangles is $2A_{2}=2\times85 = 170$ square - cm.

Step3: Calculate total surface area

The total surface area $A$ of the rectangular pyramid is the sum of the base area and the areas of the four triangular faces. So $A=A_{base}+2A_{1}+2A_{2}=289 + 170+170=629$ square - cm.

Answer:

629