which represents the polynomial below written in standard form?\n$\frac{x^{2}}{2}-3x + 4x^{3}+6$\n$6+\frac{x^…

which represents the polynomial below written in standard form?\n$\frac{x^{2}}{2}-3x + 4x^{3}+6$\n$6+\frac{x^{2}}{2}-3x + 4x^{3}$\n$4x^{3}+\frac{x^{2}}{2}-3x + 6$\n$-3x + 4x^{3}+6+\frac{x^{2}}{2}$\n$\frac{x^{2}}{2}+4x^{3}-3x + 6$

which represents the polynomial below written in standard form?\n$\frac{x^{2}}{2}-3x + 4x^{3}+6$\n$6+\frac{x^{2}}{2}-3x + 4x^{3}$\n$4x^{3}+\frac{x^{2}}{2}-3x + 6$\n$-3x + 4x^{3}+6+\frac{x^{2}}{2}$\n$\frac{x^{2}}{2}+4x^{3}-3x + 6$

Answer

Explanation:

Step1: Recall standard - form of polynomial

A polynomial in standard form is written with the terms in descending order of their degrees.

Step2: Determine degrees of each term

For the polynomial (\frac{x^{2}}{2}-3x + 4x^{3}+6), the degree of (\frac{x^{2}}{2}) is 2, the degree of (-3x) is 1, the degree of (4x^{3}) is 3, and the degree of the constant term 6 is 0.

Step3: Rearrange terms in descending - order of degrees

We start with the term of highest degree (4x^{3}), then the term with the next - highest degree (\frac{x^{2}}{2}), then the term of degree 1 (-3x), and finally the constant term 6. So the polynomial in standard form is (4x^{3}+\frac{x^{2}}{2}-3x + 6).

Answer:

(4x^{3}+\frac{x^{2}}{2}-3x + 6) (the second option)