which will result in a difference of squares?\n(-7x + 4)(-7x + 4)\n(-7x + 4)(4 - 7x)\n(-7x + 4)(-7x…

Explanation:

Step1: Recall difference - of - squares formula

The difference - of - squares formula is $(a + b)(a - b)=a^{2}-b^{2}$.

Step2: Analyze each option

For option 1: $(-7x + 4k)(-7x + 4k)=(-7x + 4k)^{2}=49x^{2}-56kx + 16k^{2}$, not a difference of squares. For option 2: $(-7x + 4k)(4 - 7x)$ is not in the form $(a + b)(a - b)$. For option 3: $(-7x + 4k)(-7x - 4k)=(-7x)^{2}-(4k)^{2}=49x^{2}-16k^{2}$, which is in the form of a difference of squares. For option 4: $(-7x + 4k)(7x - 4k)=-(7x - 4k)(7x - 4k)=-(7x - 4k)^{2}$, not a difference of squares.

Answer:

$(-7x + 4k)(-7x - 4k)$