which will result in a difference of squares? (-7x + 4)(-7x + 4) (-7x + 4)(4 - 7x) (-7x + 4)(-7x - 4) (-7x +…

Explanation:

Step1: Recall difference - of - squares formula

The difference - of - squares formula is $(a + b)(a - b)=a^{2}-b^{2}$.

Step2: Analyze each option

For the option $(-7x + 4)(-7x - 4)$, here $a=-7x$ and $b = 4$. Using the formula $(a + b)(a - b)=a^{2}-b^{2}$, we get $(-7x)^{2}-4^{2}=49x^{2}-16$. The first option $(-7x + 4)(-7x + 4)=(-7x + 4)^{2}$ is a perfect - square trinomial. The second option $(-7x + 4)(4 - 7x)=(-7x + 4)^{2}$ is also a perfect - square trinomial. The fourth option $(-7x + 4)(7x - 4)=-(7x - 4)(7x - 4)=-(7x - 4)^{2}$ is a negative of a perfect - square trinomial.

Answer:

$(-7x + 4)(-7x - 4)$