rewrite $12^{0}=1$ in logarithmic form. $square = square$

Explanation:

Step1: Recall exponent-logarithm relation

For $b^x = y$, $\log_b y = x$

Step2: Match values to the formula

Here $b=12$, $x=0$, $y=1$

Answer:

$\log_{12} 1 = 0$