rewrite the following without an exponent.\n9^{-2}

Explanation:

Step1: Apply negative - exponent rule

According to the rule $a^{-n}=\frac{1}{a^{n}}$, for $a = 9$ and $n = 2$, we have $9^{-2}=\frac{1}{9^{2}}$.

Step2: Calculate the denominator

$9^{2}=9\times9 = 81$. So, $\frac{1}{9^{2}}=\frac{1}{81}$.

Answer:

$\frac{1}{81}$