rhett is solving the quadratic equation 0 = x² - 2x - 3 using the quadratic formula. which shows the correct…

rhett is solving the quadratic equation 0 = x² - 2x - 3 using the quadratic formula. which shows the correct substitution of the values a, b, and c into the quadratic formula?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(\\frac{2\\pm\\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{-2\\pm\\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{2\\pm\\sqrt{-2^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{-2\\pm\\sqrt{-2^{2}-4(1)(-3)}}{2(1)}\\)

rhett is solving the quadratic equation 0 = x² - 2x - 3 using the quadratic formula. which shows the correct substitution of the values a, b, and c into the quadratic formula?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(\\frac{2\\pm\\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{-2\\pm\\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{2\\pm\\sqrt{-2^{2}-4(1)(-3)}}{2(1)}\\)\n\\(\\frac{-2\\pm\\sqrt{-2^{2}-4(1)(-3)}}{2(1)}\\)

Answer

Explanation:

Step1: Identify coefficients

For the quadratic equation $0 = x^{2}-2x - 3$, we have $a = 1$, $b=-2$, $c=-3$.

Step2: Substitute into formula

Substitute $a = 1$, $b=-2$, $c=-3$ into $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. We get $x=\frac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}=\frac{2\pm\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}$.

Answer:

$\frac{2\pm\sqrt{(-2)^{2}-4(1)(-3)}}{2(1)}$