which are the roots of the quadratic function f(b) = b² - 75? select two options. b = 5√3 b = -5√3 b = 3√5 b…
which are the roots of the quadratic function f(b) = b² - 75? select two options. b = 5√3 b = -5√3 b = 3√5 b = -3√5 b = 25√3
Answer
Explanation:
Step1: Set the function equal to zero
Set $f(b)=0$, so $b^{2}-75 = 0$.
Step2: Isolate $b^{2}$
Add 75 to both sides: $b^{2}=75$.
Step3: Solve for $b$
Take the square - root of both sides. Remember, $\sqrt{b^{2}}=\pm b$ and $\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}$. So $b = \pm5\sqrt{3}$.
Answer:
$b = 5\sqrt{3}$, $b=-5\sqrt{3}$