rotate $\triangle jkl$ $90^circ$ counterclockwise around the origin.
rotate $\triangle jkl$ $90^circ$ counterclockwise around the origin.
Answer
Explanation:
Step1: Identify original coordinates
From the graph: $J=(5, -5)$, $K=(15, -5)$, $L=(5, -15)$
Step2: Apply 90° counterclockwise rotation rule
The rule for rotating a point $(x,y)$ 90° counterclockwise around the origin is $(x,y) \to (-y, x)$.
- For $J=(5, -5)$: $(-(-5), 5) = (5, 5)$
- For $K=(15, -5)$: $(-(-5), 15) = (5, 15)$
- For $L=(5, -15)$: $(-(-15), 5) = (15, 5)$
Step3: Plot new points to form triangle
Connect the rotated points $J'(5,5)$, $K'(5,15)$, $L'(15,5)$ to get the rotated $\triangle J'K'L'$.
Answer:
The coordinates of the rotated triangle are: $J'(5, 5)$, $K'(5, 15)$, $L'(15, 5)$ (When plotted, these form the 90° counterclockwise rotated triangle around the origin.)