rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x²+3x - 8…

rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x²+3x - 8? quadratic formula: $x=\frac{-bpmsqrt{b^{2}-4ac}}{2a}$ 1.39 2.00 2.89 3.50
Answer
Explanation:
Step1: Identify coefficients
For the quadratic equation $0 = 2x^{2}+3x - 8$, we have $a = 2$, $b=3$, $c=-8$.
Step2: Calculate the discriminant
$\Delta=b^{2}-4ac=(3)^{2}-4\times2\times(-8)=9 + 64=73$.
Step3: Apply the quadratic formula
$x=\frac{-b\pm\sqrt{\Delta}}{2a}=\frac{-3\pm\sqrt{73}}{2\times2}=\frac{-3\pm\sqrt{73}}{4}$.
Step4: Find the positive solution
We have two solutions: $x_1=\frac{-3+\sqrt{73}}{4}$ and $x_2=\frac{-3 - \sqrt{73}}{4}$. Since $\sqrt{73}\approx8.544$, then $x_1=\frac{-3 + 8.544}{4}=\frac{5.544}{4}=1.386\approx1.39$.
Answer:
A. 1.39