a school drama department sells 40 more student tickets than adult tickets. charging $8 for adult tickets…

a school drama department sells 40 more student tickets than adult tickets. charging $8 for adult tickets and $6 for student tickets, the drama department raises a total of $1,920 in ticket sales. let x represent the number of adult tickets sold and y represent the number of student tickets sold. which system of equations can be used to find how many of each ticket is sold?\n\nx = 40 - y\n8x + 6y = 1920\n\ny = 40 - x\n8x + 6y = 1920\n\nx = 40 + y\n8x + 6y = 1920\n\ny = 40 + x\n8x + 6y = 1920

a school drama department sells 40 more student tickets than adult tickets. charging $8 for adult tickets and $6 for student tickets, the drama department raises a total of $1,920 in ticket sales. let x represent the number of adult tickets sold and y represent the number of student tickets sold. which system of equations can be used to find how many of each ticket is sold?\n\nx = 40 - y\n8x + 6y = 1920\n\ny = 40 - x\n8x + 6y = 1920\n\nx = 40 + y\n8x + 6y = 1920\n\ny = 40 + x\n8x + 6y = 1920

Answer

Explanation:

Step1: Analyze the ticket - number relationship

The drama department sells 40 more student tickets than adult tickets. If $x$ is the number of adult tickets and $y$ is the number of student tickets, then $y=x + 40$.

Step2: Analyze the money - raising relationship

Adult tickets cost $8 each and student tickets cost $6 each, and the total money raised is $1920. So the money - raising equation is $8x+6y = 1920$.

Answer:

D. $y = 40+x$, $8x+6y=1920$