what is the second term in the geometric sequence ( a_{n}=6(\frac{1}{2})^{n - 1} )?

Explanation:

Step1: Substitute (n = 2) into the formula

Given (a_{n}=6(\frac{1}{2})^{n - 1}), when (n = 2), we have (a_{2}=6(\frac{1}{2})^{2 - 1}).

Step2: Simplify the exponent

(2-1 = 1), so (a_{2}=6\times\frac{1}{2}^{1}).

Step3: Calculate the value

(6\times\frac{1}{2}=\frac{6}{2}=3).

Answer:

3