select the correct answer from each drop - down menu. consider right triangle abc. sin(a) = = cos(a) = =

select the correct answer from each drop - down menu. consider right triangle abc. sin(a) = = cos(a) = =

select the correct answer from each drop - down menu. consider right triangle abc. sin(a) = = cos(a) = =

Answer

Answer:

sin(A) = $\frac{9}{41}$, cos(A) = $\frac{40}{41}$

Explanation:

Step 1: Identify sides relative to angle A

In right triangle ABC with right angle at B:

  • Opposite side to ∠A: BC = 9
  • Adjacent side to ∠A: AB = 40
  • Hypotenuse: AC = 41

Step 2: Apply sine definition

$\sin(A) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{9}{41}$

Step 3: Apply cosine definition

$\cos(A) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{40}{41}$