select the correct answer. which inequality represents all the solutions of 10(3x + 2) > 7(2x - 4)? a. x >…

Explanation:

Step1: Expand both sides

$10(3x + 2)=30x+20$ and $7(2x - 4)=14x-28$. So the inequality becomes $30x + 20>14x-28$.

Step2: Move like - terms to one side

Subtract $14x$ from both sides: $30x-14x + 20>14x-14x-28$, which simplifies to $16x+20>-28$. Then subtract 20 from both sides: $16x+20 - 20>-28 - 20$, resulting in $16x>-48$.

Step3: Solve for x

Divide both sides by 16: $\frac{16x}{16}>\frac{-48}{16}$, so $x>-3$.

Answer:

C. $x > - 3$