a sequence is defined recursively using the equation $f(n + 1)=f(n)-8$. if $f(1)=100$, what is…

Explanation:

Step1: Find f(2)

Given (f(n + 1)=f(n)-8) and (n = 1), (f(2)=f(1)-8). Since (f(1)=100), then (f(2)=100 - 8=92).

Step2: Find f(3)

Let (n = 2), then (f(3)=f(2)-8). Substitute (f(2)=92), so (f(3)=92 - 8 = 84).

Step3: Find f(4)

Let (n=3), then (f(4)=f(3)-8). Substitute (f(3)=84), so (f(4)=84 - 8=76).

Step4: Find f(5)

Let (n = 4), then (f(5)=f(4)-8). Substitute (f(4)=76), so (f(5)=76 - 8 = 68).

Step5: Find f(6)

Let (n=5), then (f(6)=f(5)-8). Substitute (f(5)=68), so (f(6)=68 - 8=60).

Answer:

60