which set of ordered pairs represents a function?\no {(2, -2), (1, 5), (-2, 2), (1, -3), (8, -1)}\no {(3…

which set of ordered pairs represents a function?\no {(2, -2), (1, 5), (-2, 2), (1, -3), (8, -1)}\no {(3, -1), (7, 1), (-6, -1), (9, 1), (2, -1)}\no {(6, 8), (5, 2), (-2, -5), (1, -3), (-2, 9)}\no {(-3, 1), (6, 3), (-3, 2), (-3, -3), (1, -1)}
Answer
Explanation:
Step1: Recall function definition
A function is a relation where each input (x - value) has exactly one output (y - value).
Step2: Check first set
In the set ${(2,-2),(1,5),(-2,2),(1, - 3),(8,-1)}$, the x - value 1 has two different y - values (5 and - 3), so it is not a function.
Step3: Check second set
In the set ${(3,-1),(7,1),(-6,-1),(9,1),(2,-1)}$, each x - value has a unique y - value. So it is a function.
Step4: Check third set
In the set ${(6,8),(5,2),(-2,-5),(1,-3),(-2,9)}$, the x - value - 2 has two different y - values (- 5 and 9), so it is not a function.
Step5: Check fourth set
In the set ${(-3,1),(6,3),(-3,2),(-3,-3),(1,-1)}$, the x - value - 3 has three different y - values (1, 2 and - 3), so it is not a function.
Answer:
${(3,-1),(7,1),(-6,-1),(9,1),(2,-1)}$