which shows the correct substitution of the values a, b, and c from the equation 0 = - 3x² - 2x + 6 into the…

which shows the correct substitution of the values a, b, and c from the equation 0 = - 3x² - 2x + 6 into the quadratic formula?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(x = \\frac{-(-2)\\pm\\sqrt{(-2)^{2}-4(-3)(6)}}{2(-3)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(-3)(6)}}{2(-3)}\\)\n\\(x = \\frac{-(-2)\\pm\\sqrt{(-2)^{2}-4(3)(6)}}{2(3)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(3)(6)}}{2(3)}\\)

which shows the correct substitution of the values a, b, and c from the equation 0 = - 3x² - 2x + 6 into the quadratic formula?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(x = \\frac{-(-2)\\pm\\sqrt{(-2)^{2}-4(-3)(6)}}{2(-3)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(-3)(6)}}{2(-3)}\\)\n\\(x = \\frac{-(-2)\\pm\\sqrt{(-2)^{2}-4(3)(6)}}{2(3)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(3)(6)}}{2(3)}\\)

Answer

Explanation:

Step1: Identify a, b, c values

For the quadratic equation $0=-3x^{2}-2x + 6$, we have $a=-3$, $b=-2$, $c = 6$.

Step2: Substitute into quadratic formula

The quadratic formula is $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Substituting $a=-3$, $b=-2$, $c = 6$ gives $x=\frac{-(-2)\pm\sqrt{(-2)^{2}-4(-3)(6)}}{2(-3)}$.

Answer:

$x=\frac{-(-2)\pm\sqrt{(-2)^{2}-4(-3)(6)}}{2(-3)}$