which shows the correct substitution of the values a, b, and c from the equation 0 = 4x² + 2x - 1 into the…

which shows the correct substitution of the values a, b, and c from the equation 0 = 4x² + 2x - 1 into the quadratic formula below?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(4)(-1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(4)(1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}+4(4)(-1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{-2^{2}-4(4)(-1)}}{2(4)}\\)

which shows the correct substitution of the values a, b, and c from the equation 0 = 4x² + 2x - 1 into the quadratic formula below?\nquadratic formula: x = \\frac{-b\\pm\\sqrt{b^{2}-4ac}}{2a}\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(4)(-1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}-4(4)(1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{2^{2}+4(4)(-1)}}{2(4)}\\)\n\\(x = \\frac{-2\\pm\\sqrt{-2^{2}-4(4)(-1)}}{2(4)}\\)

Answer

Explanation:

Step1: Identify a, b, c values

For the quadratic equation $0 = 4x^{2}+2x - 1$, we have $a = 4$, $b = 2$, $c=-1$.

Step2: Substitute into quadratic formula

Substitute $a = 4$, $b = 2$, $c=-1$ into $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. We get $x=\frac{-2\pm\sqrt{2^{2}-4(4)(-1)}}{2(4)}$.

Answer:

$x=\frac{-2\pm\sqrt{2^{2}-4(4)(-1)}}{2(4)}$ (First option)