which shows the following expression after the negative exponents have been eliminated?\n\\( \\frac { m ^ {…

which shows the following expression after the negative exponents have been eliminated?\n\\( \\frac { m ^ { 7 } n ^ { 3 } } { m n ^ { - 1 } }, m \\neq 0, n \\neq 0 \\)

which shows the following expression after the negative exponents have been eliminated?\n\\( \\frac { m ^ { 7 } n ^ { 3 } } { m n ^ { - 1 } }, m \\neq 0, n \\neq 0 \\)

Answer

Explanation:

Step1: Apply the negative exponent rule (a^{-b}=\frac{1}{a^{b}})

For (n^{-1}), we have (n^{-1}=\frac{1}{n}), so (\frac{m^{7}n^{3}}{mn^{-1}}=\frac{m^{7}n^{3}}{\frac{m}{n}})

Step2: Divide by a fraction (multiply by its reciprocal)

(\frac{m^{7}n^{3}}{\frac{m}{n}}=m^{7}n^{3}\times\frac{n}{m})

Step3: Simplify using the rule (a^{m}\div a^{n}=a^{m - n}) and (a^{m}\times a^{n}=a^{m + n})

(m^{7}n^{3}\times\frac{n}{m}=\frac{m^{7}n^{3}n}{m}) (since (n^{3}\times n=n^{3 + 1}=n^{4}) and (m^{7}\div m=m^{7-1}=m^{6}))

Answer:

(\frac{m^{7}n^{3}n}{m})