which shows one way to determine the factors of $12x^{3}-2x^{2}+18x - 3$ by grouping?\n$2x^{2}(6x - 1)+3(6x…

which shows one way to determine the factors of $12x^{3}-2x^{2}+18x - 3$ by grouping?\n$2x^{2}(6x - 1)+3(6x - 1)$\n$2x^{2}(6x - 1)-3(6x - 1)$\n$6x(2x^{2}-3)-1(2x^{2}-3)$\n$6x(2x^{2}+3)+1(2x^{2}+3)$

which shows one way to determine the factors of $12x^{3}-2x^{2}+18x - 3$ by grouping?\n$2x^{2}(6x - 1)+3(6x - 1)$\n$2x^{2}(6x - 1)-3(6x - 1)$\n$6x(2x^{2}-3)-1(2x^{2}-3)$\n$6x(2x^{2}+3)+1(2x^{2}+3)$

Answer

Explanation:

Step1: Group the terms

Group the polynomial $12x^{3}-2x^{2}+18x - 3$ as $(12x^{3}-2x^{2})+(18x - 3)$.

Step2: Factor out the GCF from each group

From the first - group $12x^{3}-2x^{2}$, the GCF is $2x^{2}$, so $12x^{3}-2x^{2}=2x^{2}(6x - 1)$. From the second - group $18x - 3$, the GCF is 3, so $18x - 3=3(6x - 1)$.

Step3: Rewrite the polynomial

The polynomial becomes $2x^{2}(6x - 1)+3(6x - 1)$.

Answer:

A. $2x^{2}(6x - 1)+3(6x - 1)$