which shows one way to determine the factors of $x^{3}+4x^{2}+5x + 20$ by grouping?\n$x(x^{2}+4)+5(x^{2}+4)$\…

which shows one way to determine the factors of $x^{3}+4x^{2}+5x + 20$ by grouping?\n$x(x^{2}+4)+5(x^{2}+4)$\n$x^{2}(x + 4)+5(x + 4)$\n$x^{2}(x + 5)+4(x + 5)$\n$x(x^{2}+5)+4x(x^{2}+5)$

which shows one way to determine the factors of $x^{3}+4x^{2}+5x + 20$ by grouping?\n$x(x^{2}+4)+5(x^{2}+4)$\n$x^{2}(x + 4)+5(x + 4)$\n$x^{2}(x + 5)+4(x + 5)$\n$x(x^{2}+5)+4x(x^{2}+5)$

Answer

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms of the polynomial (x^{3}+4x^{2}+5x + 20). We get ((x^{3}+4x^{2})+(5x + 20)).

Step2: Factor out the GCF from each group

From the first - group (x^{3}+4x^{2}), the greatest common factor (GCF) is (x^{2}), so (x^{3}+4x^{2}=x^{2}(x + 4)). From the second - group (5x + 20), the GCF is 5, so (5x + 20=5(x + 4)).

Step3: Rewrite the polynomial

The polynomial ((x^{3}+4x^{2})+(5x + 20)) can be rewritten as (x^{2}(x + 4)+5(x + 4)).

Answer:

(x^{2}(x + 4)+5(x + 4)) (the second option)