which shows one way to determine the factors of $4x^{3}+x^{2}-8x - 2$ by grouping?\n$x^{2}(4x + 1)-2(4x +…

which shows one way to determine the factors of $4x^{3}+x^{2}-8x - 2$ by grouping?\n$x^{2}(4x + 1)-2(4x + 1)$\n$x^{2}(4x - 1)+2(4x - 1)$\n$4x^{2}(x + 2)-1(x + 2)$\n$4x^{2}(x - 2)-1(x - 2)$

which shows one way to determine the factors of $4x^{3}+x^{2}-8x - 2$ by grouping?\n$x^{2}(4x + 1)-2(4x + 1)$\n$x^{2}(4x - 1)+2(4x - 1)$\n$4x^{2}(x + 2)-1(x + 2)$\n$4x^{2}(x - 2)-1(x - 2)$

Answer

Answer:

A. $x^{2}(4x + 1)-2(4x + 1)$

Explanation:

Step1: Group the terms

Group $4x^{3}+x^{2}-8x - 2$ as $(4x^{3}+x^{2})+(-8x - 2)$.

Step2: Factor out GCF from each group

From $4x^{3}+x^{2}$, factor out $x^{2}$ to get $x^{2}(4x + 1)$. From $-8x - 2$, factor out $- 2$ to get $-2(4x + 1)$. So the expression becomes $x^{2}(4x + 1)-2(4x + 1)$.