which is the simplified form of $m^{-8}p^{0}$?\n$\frac{1}{m^{8}p}$\n$\frac{1}{m^{8}}$\n$\frac{p}{m^{8}}$\n$m^…
which is the simplified form of $m^{-8}p^{0}$?\n$\frac{1}{m^{8}p}$\n$\frac{1}{m^{8}}$\n$\frac{p}{m^{8}}$\n$m^{8}$
Answer
Explanation:
Step1: Apply zero - exponent rule
Any non - zero number to the power of 0 is 1. So, $p^{0}=1$. The expression becomes $m^{-8}\times1 = m^{-8}$.
Step2: Apply negative - exponent rule
The negative - exponent rule states that $a^{-n}=\frac{1}{a^{n}}$. For $m^{-8}$, we have $m^{-8}=\frac{1}{m^{8}}$.
Answer:
$\frac{1}{m^{8}}$