what is the simplified form of $sqrt{\frac{48}{192}}$?\n$\frac{1}{4}$\n$\frac{1}{2}$\n$2$\n$4$

Explanation:

Step1: Simplify the fraction inside square - root

First, simplify $\frac{48}{192}$. Divide both the numerator and denominator by their greatest - common divisor, which is 48. So, $\frac{48\div48}{192\div48}=\frac{1}{4}$.

Step2: Calculate the square - root

Then, find $\sqrt{\frac{1}{4}}$. Since $\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ ($a = 1$, $b = 4$), and $\sqrt{1}=1$, $\sqrt{4}=2$, we have $\sqrt{\frac{1}{4}}=\frac{1}{2}$.

Answer:

B. $\frac{1}{2}$