simplify. assume s is greater than or equal to zero. $sqrt{45s^{3}}$

simplify. assume s is greater than or equal to zero. $sqrt{45s^{3}}$
Answer
Answer:
$3s\sqrt{5s}$
Explanation:
Step1: Factor 45 and $s^3$
$\sqrt{45s^{3}}=\sqrt{9\times5\times s^{2}\times s}$
Step2: Use square - root property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$
$\sqrt{9\times5\times s^{2}\times s}=\sqrt{9}\times\sqrt{5}\times\sqrt{s^{2}}\times\sqrt{s}$
Step3: Simplify square - roots
$\sqrt{9} = 3$, $\sqrt{s^{2}}=s$ (since $s\geq0$), so $3\times\sqrt{5}\times s\times\sqrt{s}=3s\sqrt{5s}$