simplify the followin radical expression. \n\n sqrt{63} \n\n ? sqrt{}

Explanation:

Step1: Factorize the number inside the radical

Factorize (63) into prime factors: (63 = 9\times7). So, (\sqrt{63}=\sqrt{9\times7}).

Step2: Use the property of square roots (\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}) ((a\geq0,b\geq0))

We know that (\sqrt{9\times7}=\sqrt{9}\cdot\sqrt{7}). Since (\sqrt{9} = 3), then (\sqrt{63}=3\sqrt{7}).

Answer:

(3\sqrt{7})