simplify the following expression.\n(4g + 19)(4g - 19)\n?g² -

Explanation:

Step1: Apply difference - of - squares formula

We use the formula $(a + b)(a - b)=a^{2}-b^{2}$, where $a = 4g$ and $b = 19$. $(4g + 19)(4g - 19)=(4g)^{2}-19^{2}$

Step2: Calculate the squares

$(4g)^{2}=4^{2}\times g^{2}=16g^{2}$ and $19^{2}=361$. So, $(4g)^{2}-19^{2}=16g^{2}-361$

Answer:

$16g^{2}-361$