simplify.\n$\frac{12u^{2}-8u}{4u^{2}-32u}$

Explanation:

Step1: Factor out the GCF from numerator and denominator

The GCF of $12u^{2}-8u$ is $4u$, so $12u^{2}-8u = 4u(3u - 2)$. The GCF of $4u^{2}-32u$ is $4u$, so $4u^{2}-32u=4u(u - 8)$.

Step2: Simplify the fraction

$\frac{4u(3u - 2)}{4u(u - 8)}=\frac{3u - 2}{u - 8}$, where $u\neq0$.

Answer:

$\frac{3u - 2}{u - 8},u\neq0$