simplify $\frac{12y^{7}}{18y^{-3}}$. assume $y\neq0$.\n$\frac{y^{10}}{6}$\n$\frac{2}{3y^{10}}$\n$\frac{2y^{10…

simplify $\frac{12y^{7}}{18y^{-3}}$. assume $y\neq0$.\n$\frac{y^{10}}{6}$\n$\frac{2}{3y^{10}}$\n$\frac{2y^{10}}{3}$

simplify $\frac{12y^{7}}{18y^{-3}}$. assume $y\neq0$.\n$\frac{y^{10}}{6}$\n$\frac{2}{3y^{10}}$\n$\frac{2y^{10}}{3}$

Answer

Explanation:

Step1: Simplify coefficient

$\frac{12}{18}=\frac{2}{3}$

Step2: Use exponent - division rule

$\frac{y^{7}}{y^{- 3}}=y^{7-(-3)} = y^{10}$

Step3: Combine results

$\frac{2}{3}\times y^{10}=\frac{2y^{10}}{3}$

Answer:

$\frac{2y^{10}}{3}$