simplify:\n$\frac{3x^{2}}{x^{2}-x - 30}-\frac{3x + 5}{x - 6}$\n$\frac{?x+}{(x - 6)(x+)}$

Explanation:

Step1: Factor the denominator

Factor $x^{2}-x - 30$ as $(x - 6)(x+5)$. So the expression becomes $\frac{3x^{2}}{(x - 6)(x + 5)}-\frac{3x + 5}{x - 6}$.

Step2: Find a common - denominator

The common denominator is $(x - 6)(x + 5)$. Rewrite the second fraction as $\frac{(3x + 5)(x + 5)}{(x - 6)(x + 5)}$.

Step3: Subtract the fractions

$\frac{3x^{2}-(3x + 5)(x + 5)}{(x - 6)(x + 5)}=\frac{3x^{2}-(3x^{2}+15x+5x + 25)}{(x - 6)(x + 5)}$.

Step4: Expand and simplify the numerator

$3x^{2}-(3x^{2}+20x + 25)=3x^{2}-3x^{2}-20x - 25=-20x-25$.

Answer:

$\frac{-20x - 25}{(x - 6)(x + 5)}$