simplify.\n$sqrt{147}$

Explanation:

Step1: Prime - factorize 147

$147 = 3\times49=3\times7\times7$

Step2: Apply square - root property

$\sqrt{147}=\sqrt{3\times7^{2}}$ Since $\sqrt{ab}=\sqrt{a}\times\sqrt{b}$ ($a = 3$, $b = 7^{2}$), we have $\sqrt{3\times7^{2}}=\sqrt{3}\times\sqrt{7^{2}}$ And $\sqrt{7^{2}} = 7$, so $\sqrt{147}=7\sqrt{3}$

Answer:

$7\sqrt{3}$