simplify. \n\\sqrt{63}

Explanation:

Step1: Factor 63 into prime factors

We know that (63 = 9\times7), and (9 = 3^2) is a perfect square. So we can rewrite (\sqrt{63}) as (\sqrt{9\times7}).

Step2: Use the property of square roots (\sqrt{ab}=\sqrt{a}\times\sqrt{b}) (where (a\geq0,b\geq0))

Applying this property, we get (\sqrt{9\times7}=\sqrt{9}\times\sqrt{7}). Since (\sqrt{9} = 3), then (\sqrt{9}\times\sqrt{7}=3\sqrt{7}).

Answer:

(3\sqrt{7})