simplify.\n$sqrt3{6}+sqrt3{48}$

Explanation:

Step1: Factorize 48

We know that $48 = 8\times6$. So, $\sqrt[3]{48}=\sqrt[3]{8\times6}$.

Step2: Use the cube - root property $\sqrt[3]{ab}=\sqrt[3]{a}\times\sqrt[3]{b}$

Since $\sqrt[3]{8} = 2$, then $\sqrt[3]{48}=\sqrt[3]{8\times6}=\sqrt[3]{8}\times\sqrt[3]{6}=2\sqrt[3]{6}$.

Step3: Combine like terms

$\sqrt[3]{6}+\sqrt[3]{48}=\sqrt[3]{6}+2\sqrt[3]{6}=(1 + 2)\sqrt[3]{6}=3\sqrt[3]{6}$.

Answer:

$3\sqrt[3]{6}$