simplify by using long division. write the expression in standard form. $(2t^{2}+13t + 15)div(t + 6)$
simplify by using long division. write the expression in standard form. $(2t^{2}+13t + 15)div(t + 6)$
Answer
Explanation:
Step1: Divide the leading terms
Divide (2t^{2}) by (t). (\frac{2t^{2}}{t}=2t). Multiply ((t + 6)) by (2t): (2t(t + 6)=2t^{2}+12t). Subtract (2t^{2}+12t) from (2t^{2}+13t + 15): ((2t^{2}+13t + 15)-(2t^{2}+12t)=t + 15).
Step2: Divide the new leading terms
Divide (t) by (t). (\frac{t}{t}=1). Multiply ((t + 6)) by (1): (1\times(t + 6)=t + 6). Subtract (t + 6) from (t + 15): ((t + 15)-(t + 6)=9).
Answer:
(2t + 1+\frac{9}{t + 6})