six teammates are competing for first, second, and third place in a race. how many possibilities are there…

six teammates are competing for first, second, and third place in a race. how many possibilities are there for the top three positions?\no 20\no 30\no 120\no 240
Answer
Explanation:
Step1: Identify permutation formula
The formula for permutations is $P(n,r)=\frac{n!}{(n - r)!}$, where $n$ is the total number of items and $r$ is the number of items to be selected. Here $n = 6$ (number of teammates) and $r=3$ (top - three positions).
Step2: Calculate factorial values
$n!=6!=6\times5\times4\times3\times2\times1 = 720$ and $(n - r)!=(6 - 3)!=3!=3\times2\times1=6$.
Step3: Compute the permutation
$P(6,3)=\frac{6!}{(6 - 3)!}=\frac{720}{6}=120$.
Answer:
C. 120