what is the slope of a line that is perpendicular to the line y = 8x + 5?\n-8\n-\\frac{1}{8}\n\\frac{1}{8}\n8
what is the slope of a line that is perpendicular to the line y = 8x + 5?\n-8\n-\\frac{1}{8}\n\\frac{1}{8}\n8
Answer
Explanation:
Step1: Identify slope of given line
The equation of the given line is in slope - intercept form $y = mx + b$, where $m$ is the slope. For the line $y = 8x+5$, the slope $m_1 = 8$.
Step2: Use perpendicular - slope formula
If two lines with slopes $m_1$ and $m_2$ are perpendicular, then $m_1\times m_2=- 1$. We know $m_1 = 8$, so $8\times m_2=-1$. Solving for $m_2$, we get $m_2=-\frac{1}{8}$.
Answer:
B. $-\frac{1}{8}$