what is the slope of a line that is perpendicular to the line y = -\\frac{1}{2}x + 5?\n-2\n-\\frac{1}{2}\n\\f…

what is the slope of a line that is perpendicular to the line y = -\\frac{1}{2}x + 5?\n-2\n-\\frac{1}{2}\n\\frac{1}{2}\n2

what is the slope of a line that is perpendicular to the line y = -\\frac{1}{2}x + 5?\n-2\n-\\frac{1}{2}\n\\frac{1}{2}\n2

Answer

Answer:

D. 2

Explanation:

Step1: Recall slope - perpendicular line relation

The product of slopes of two perpendicular lines is - 1. Let the slope of the given line be $m_1$ and the slope of the perpendicular line be $m_2$. So $m_1\times m_2=-1$.

Step2: Identify the slope of the given line

The equation of the given line is $y =-\frac{1}{2}x + 5$, which is in the slope - intercept form $y=mx + b$ where $m$ is the slope. So $m_1=-\frac{1}{2}$.

Step3: Calculate the slope of the perpendicular line

Substitute $m_1 =-\frac{1}{2}$ into $m_1\times m_2=-1$. We get $-\frac{1}{2}\times m_2=-1$. Solving for $m_2$, we multiply both sides by - 2, so $m_2 = 2$.