what is the slope of the line represented by the equation $y = -\frac{1}{2}x+\frac{1}{4}$?\n$-\frac{1}{2}$\n$…

what is the slope of the line represented by the equation $y = -\frac{1}{2}x+\frac{1}{4}$?\n$-\frac{1}{2}$\n$-\frac{1}{4}$\n$\frac{1}{4}$\n$\frac{1}{2}$

what is the slope of the line represented by the equation $y = -\frac{1}{2}x+\frac{1}{4}$?\n$-\frac{1}{2}$\n$-\frac{1}{4}$\n$\frac{1}{4}$\n$\frac{1}{2}$

Answer

Answer:

A. $-\frac{1}{2}$

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.

Step2: Identify the slope

In the equation $y=-\frac{1}{2}x+\frac{1}{4}$, comparing with $y = mx + b$, we have $m = -\frac{1}{2}$. So the slope of the line is $-\frac{1}{2}$.