a soccer team ordered 12 jerseys and 12 pairs of shorts, for a total of $156. later, they had to order 4…

a soccer team ordered 12 jerseys and 12 pairs of shorts, for a total of $156. later, they had to order 4 more jerseys and 6 more pairs of shorts, for a total of $62. the system of equations that can be used to find x, the cost of each jersey, and y, the cost of each pair of shorts is shown. 12x + 12y = 156 4x + 6y = 62 what is the cost of each jersey? $5 $8 $12 $13

a soccer team ordered 12 jerseys and 12 pairs of shorts, for a total of $156. later, they had to order 4 more jerseys and 6 more pairs of shorts, for a total of $62. the system of equations that can be used to find x, the cost of each jersey, and y, the cost of each pair of shorts is shown. 12x + 12y = 156 4x + 6y = 62 what is the cost of each jersey? $5 $8 $12 $13

Answer

Explanation:

Step1: Simplify first equation

Divide $12x + 12y=156$ by 12, we get $x + y = 13$, so $y=13 - x$.

Step2: Substitute into second - equation

Substitute $y = 13 - x$ into $4x+6y = 62$. Then $4x+6(13 - x)=62$.

Step3: Expand and solve for x

Expand: $4x+78 - 6x=62$. Combine like - terms: $- 2x=62 - 78=-16$. Divide both sides by $-2$, $x = 8$.

Answer:

$8$