a solid right pyramid has a square base. the base edge length is 2 cm longer than the height of the pyramid…

Explanation:

Step1: Find base - edge length

The height $h = 6$ cm. The base - edge length $s$ is 2 cm longer than the height, so $s=h + 2=6 + 2=8$ cm.

Step2: Calculate base area

The base is a square. The area of a square $A=s^{2}$, so $A = 8^{2}=64$ $cm^{2}$.

Step3: Calculate volume of the pyramid

The volume formula of a pyramid is $V=\frac{1}{3}Ah$, where $A$ is the base area and $h$ is the height. Substitute $A = 64$ $cm^{2}$ and $h = 6$ cm into the formula: $V=\frac{1}{3}\times64\times6=128$ $cm^{3}$.

Answer:

$128$ $cm^{3}$