what are the solution(s) of $x^{2}-4 = 0$?\n$x=-4$ or $x = 4$\n$x=-2$ or $x = 2$\n$x = 2$\n$x = 4$

what are the solution(s) of $x^{2}-4 = 0$?\n$x=-4$ or $x = 4$\n$x=-2$ or $x = 2$\n$x = 2$\n$x = 4$

what are the solution(s) of $x^{2}-4 = 0$?\n$x=-4$ or $x = 4$\n$x=-2$ or $x = 2$\n$x = 2$\n$x = 4$

Answer

Explanation:

Step1: Isolate the variable term

Add 4 to both sides of the equation $x^{2}-4 = 0$. We get $x^{2}=4$.

Step2: Solve for x

Take the square - root of both sides. Since $x^{2}=4$, then $x=\pm\sqrt{4}$. So $x = 2$ or $x=-2$.

Answer:

$x=-2$ or $x = 2$