which is a solution to (x - 3)(x + 9) = -27?\no x = -9\no x = -3\no x = 0\no x = 6

Explanation:

Step1: Expand the left - hand side

$(x - 3)(x + 9)=x^{2}+9x-3x - 27=x^{2}+6x - 27$ So the equation becomes $x^{2}+6x - 27=-27$.

Step2: Simplify the equation

Add 27 to both sides of the equation: $x^{2}+6x-27 + 27=-27 + 27$ $x^{2}+6x=0$

Step3: Factor the left - hand side

Factor out an $x$: $x(x + 6)=0$

Step4: Solve for $x$

Set each factor equal to zero: If $x=0$, the equation is satisfied. If $x+6 = 0$, then $x=-6$.

Among the given options, the solution is $x = 0$.

Answer:

C. $x = 0$