what is the solution to 3|-3x + 9| = -18?\no x = -5\no x = 5 or x = 1\no x = -5 or x = 1\no no solution

Explanation:

Step1: Isolate the absolute - value expression

Divide both sides of the equation $3|-3x + 9|=-18$ by 3. $|-3x + 9|=\frac{-18}{3}=-6$

Step2: Analyze the absolute - value property

The absolute - value of any real number $a$, denoted as $|a|$, is defined as $|a|=\begin{cases}a, & a\geq0\-a, & a < 0\end{cases}$, and $|a|\geq0$ for all real numbers $a$. Since the absolute - value of an expression $|-3x + 9|$ cannot be negative ($|-3x + 9|\geq0$ for all real $x$), and we have $|-3x + 9|=-6$ (where $-6<0$), there are no real - number solutions for $x$.

Answer:

no solution