what is a solution to (x + 6)(x + 2) = 60?\no x = -6\no x = -4\no x = 4\no x = 12

Explanation:

Step1: Expand the left - hand side

$(x + 6)(x + 2)=x^{2}+2x+6x + 12=x^{2}+8x + 12$ So the equation becomes $x^{2}+8x + 12=60$.

Step2: Rearrange to standard quadratic form

Subtract 60 from both sides: $x^{2}+8x+12 - 60=0$, which simplifies to $x^{2}+8x - 48=0$.

Step3: Factor the quadratic equation

We need to find two numbers that multiply to - 48 and add up to 8. The numbers are 12 and - 4. So $x^{2}+8x - 48=(x + 12)(x - 4)=0$.

Step4: Solve for x

Set each factor equal to zero: If $x+12 = 0$, then $x=-12$; if $x - 4=0$, then $x = 4$.

Answer:

C. $x = 4$