what is the solution to the equation 2^{x + 4}-12 = 20?\no x = 0\no x = 1\no x = 2\no x = 9

Explanation:

Step1: Isolate the exponential term

Add 12 to both sides of the equation $2^{x + 4}-12 = 20$. $2^{x + 4}=20 + 12$ $2^{x + 4}=32$

Step2: Rewrite 32 as a power of 2

Since $32=2^5$, the equation becomes $2^{x + 4}=2^5$.

Step3: Equate the exponents

If $a^m=a^n$, then $m = n$. So $x + 4=5$.

Step4: Solve for x

Subtract 4 from both sides: $x=5 - 4$ $x = 1$

Answer:

$x = 1$