what is the solution to $-\\frac{3}{4}x + 2 \\leq -7$?\n\n$x \\geq -12$\n$x \\geq 12$\n$x \\leq 12$\n$x…

what is the solution to $-\\frac{3}{4}x + 2 \\leq -7$?\n\n$x \\geq -12$\n$x \\geq 12$\n$x \\leq 12$\n$x \\leq -12$

what is the solution to $-\\frac{3}{4}x + 2 \\leq -7$?\n\n$x \\geq -12$\n$x \\geq 12$\n$x \\leq 12$\n$x \\leq -12$

Answer

Explanation:

Step1: Subtract constant from both sides

$$-\frac{3}{4}x \leq -7 - 2$$

Step2: Simplify the right side

$$-\frac{3}{4}x \leq -9$$

Step3: Multiply by reciprocal and flip inequality

$$x \geq -9 \cdot \left(-\frac{4}{3}\right)$$

Step4: Calculate the final value

$$x \geq 12$$

Answer:

x \geq 12